Hi All,
Tile1 Tile2 Tile3
Tile4 Tile5 Tile6
Outlook
Tile7 Tile8 Tile9
I have 9 tiles and i required to show the tiles in rows and columns which I am able to achieve that with below snippet of jquery script.But i required to show information as "outlook" before third row as mentioned in below example .Can any one help me how can I achieve this
exampleTile1 Tile2 Tile3
Tile4 Tile5 Tile6
Outlook
Tile7 Tile8 Tile9
<script type="text/javascript" src="https://microsoft.sharepoint.com/teams/EDSCI/Style%20Library/jquery-1.10.2.js"></script>
<script type="text/javascript">
$(document).ready(function () {
// Update this value to the number of links you want to show per row
var numberOfLinksPerRow = 3;
// local variables
var pre = "<tr><td><div class='ms-promlink-body' id='promlink_row_";
var post = "'></div></td></tr>";
var numberOfLinksInCurrentRow = numberOfLinksPerRow;
var currentRow = 1
// find the number of promoted links we're displaying
var numberOfPromotedLinks = $('.ms-promlink-body > .ms-tileview-tile-root').length;
// if we have more links then we want in a row, let's continue
if (numberOfPromotedLinks > numberOfLinksPerRow) {
// we don't need the header anymore, no cycling through links
$('.ms-promlink-root > .ms-promlink-header').empty();
// let's iterate through all the links after the maximum displayed link
for (i = numberOfLinksPerRow + 1; i <= numberOfPromotedLinks; i++) {
// if we're reached the maximum number of links to show per row, add a new row
// this happens the first time, with the values set initially
if (numberOfLinksInCurrentRow == numberOfLinksPerRow) {
// i just want the 2nd row to
currentRow++;
// create a new row of links
$('.ms-promlink-root > table > tbody:last').append(pre + currentRow + post);
// reset the number of links for the current row
numberOfLinksInCurrentRow = 0 }
// move the Nth (numberOfLinksPerRow + 1) div to the current table row
$('#promlink_row_' + currentRow).append($('.ms-promlink-body > .ms-tileview-tile-root:eq(' + (numberOfLinksPerRow) + ')'));
// increment the number of links in the current row
numberOfLinksInCurrentRow++; }
}
});
</script>